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Subarray Sums Divisible by K (medium)
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Problem Statement

Given an array of integers nums and an integer k, return the count of non-empty subarrays that have a sum that is divisible by k.

A subarray is a continuous part of an array.

Examples

Example 1

  • Input: nums = [3, 1, 2, -2, 5, -1], k = 3
  • Expected Output: 7
  • Justification: The subarrays that sum to a multiple of 3 are [3], [1, 2], [3, 1, 2], [3, 1, 2, -2, 5], [1, 2, -2, 5], [-2, 5], and [2, -2].

Example 2

  • Input: nums = [4, 5, 0, -2, -3, 1], k = 5
  • Expected Output: 7
  • Justification: The subarrays that sum to a multiple of 5 are [5], [4, 5, 0, -2, -3, 1], [5, 0], [0], [5, 0, -2, -3], [0, -2, -3], and [-2, -3].

Example 3

  • Input: nums = [-1, 2, 9], k = 2
  • Expected Output: 2
  • Justification: The subarrays that sum to a multiple of 2 are [2] and [-1, 2, 9].

Constraints:

  • 1 <= nums.length <= 3 * 10<sup>4</sup>
  • -10<sup>4</sup> <= nums[i] <= 10<sup>4</sup>
  • 2 <= k <= 10<sup>4</sup>

Constraints:

  • 1 <= nums.length <= 3 * 10<sup>4</sup>
  • nums[i] is either 0 or 1.
  • 0 <= goal <= nums.length

Try it yourself

Try solving this question here:

Python3
Python3

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