824. Goat Latin - Detailed Explanation
Problem Statement
You are given a sentence containing words separated by spaces. Your task is to convert the sentence to "Goat Latin" using the following rules:
-
If a word begins with a vowel (a, e, i, o, u, in either uppercase or lowercase), append "ma" to the end of the word.
-
If a word begins with a consonant, remove the first letter, append it to the end of the word, and then add "ma".
-
After applying the above rule to each word, append one letter 'a' to the end of each word per its word index in the sentence, starting with 1. For the first word, add "a"; for the second word, add "aa"; for the third word, add "aaa"; and so on.
Example 1
- Input:
"I speak Goat Latin"
- Output:
"Imaa peaksmaaa oatGmaaaa atinLmaaaaa"
- Explanation:
- Word 1:
"I"
→ Vowel, so becomes"I" + "ma" + "a"
="Imaa"
- Word 2:
"speak"
→ Consonant, so becomes"peak" + "s" + "ma" + "aa"
="peaksmaaa"
- Word 3:
"Goat"
→ Consonant, so becomes"oat" + "G" + "ma" + "aaa"
="oatGmaaaa"
- Word 4:
"Latin"
→ Consonant, so becomes"atin" + "L" + "ma" + "aaaa"
="atinLmaaaaa"
- Word 1:
Example 2
- Input:
"The quick brown fox jumped over the lazy dog"
- Output:
- Transformation is done word by word using the same rules.
- For example,
"The"
becomes"heTmaa"
(since 'T' is a consonant) and so on for each word.
Example 3
- Input:
"apple"
- Output:
"applemaa"
- Explanation:
- Since
"apple"
starts with a vowel, simply append"ma"
and then add one"a"
for the first word.
- Since
Constraints:
- The input sentence is a non-empty string.
- The sentence contains words separated by single spaces.
- Each word consists only of uppercase and lowercase letters.
Hints
-
Hint 1:
Start by splitting the sentence into individual words. Process each word one by one and keep track of the word index to append the correct number of "a"s at the end. -
Hint 2:
Use a set or string containing vowels (both uppercase and lowercase) to easily check if a word starts with a vowel. For each word, based on whether the first character is a vowel or consonant, perform the required transformation.
Approach 1: Brute Force / Straightforward String Manipulation
Explanation
- Step 1: Split the input sentence into words using the space as a delimiter.
- Step 2: Iterate over each word while keeping track of its index (starting from 1).
- Step 3: For each word:
- Check if the first letter is a vowel.
- If yes, append "ma" directly to the word.
- If no, remove the first character, append it to the end of the word, then append "ma".
- Check if the first letter is a vowel.
- Step 4: Append additional "a"s equal to the current word index.
- Step 5: Combine all the transformed words back into a single string with spaces.
Visual Example (Using "I speak Goat Latin")
-
Split:
["I", "speak", "Goat", "Latin"]
-
Processing:
- Word 1 ("I"):
- Starts with vowel →
"I" + "ma" = "Ima"
- Append one "a":
"Imaa"
- Starts with vowel →
- Word 2 ("speak"):
- Starts with consonant → Remove
"s"
, then"peak" + "s" = "peaks"
- Append "ma":
"peaksma"
- Append two "a"s:
"peaksmaaa"
- Starts with consonant → Remove
- Word 3 ("Goat"):
- Starts with consonant → Remove
"G"
, then"oat" + "G" = "oatG"
- Append "ma":
"oatGma"
- Append three "a"s:
"oatGmaaaa"
- Starts with consonant → Remove
- Word 4 ("Latin"):
- Starts with consonant → Remove
"L"
, then"atin" + "L" = "atinL"
- Append "ma":
"atinLma"
- Append four "a"s:
"atinLmaaaaa"
- Starts with consonant → Remove
- Word 1 ("I"):
-
Join:
Combine the processed words with a space:
"Imaa peaksmaaa oatGmaaaa atinLmaaaaa"
Approach 2: Optimal/Concise Approach
Explanation
The brute force approach described is already optimal for this problem since the overall work is proportional to the number of characters in the sentence. An alternative concise solution might leverage Python’s list comprehension or Java’s StringBuilder in a more compact format. However, the fundamental steps remain the same:
- Split the sentence.
- Process each word using the vowel/consonant rules.
- Append the "ma" and extra "a"s.
- Join the words back into a sentence.
This approach runs in linear time with respect to the total number of characters in the sentence.
Complexity Analysis
-
Time Complexity: O(n) where n is the total number of characters in the input sentence. Each character is processed a constant number of times.
-
Space Complexity: O(n) for storing the list of words and the final result.
Code in Python
Code in Java
Step-by-Step Walkthrough and Visual Examples
-
Splitting the Sentence:
- Input:
"I speak Goat Latin"
- Result after splitting:
["I", "speak", "Goat", "Latin"]
- Input:
-
Processing Each Word:
- For
"I"
(word 1):- Check: 'I' is a vowel
- Transformation:
"I" + "ma" + "a"
→"Imaa"
- For
"speak"
(word 2):- Check: 's' is a consonant
- Transformation: Remove 's' →
"peak"
, then"peak" + "s" + "ma" + "aa"
→"peaksmaaa"
- For
"Goat"
(word 3):- Check: 'G' is a consonant
- Transformation: Remove 'G' →
"oat"
, then"oat" + "G" + "ma" + "aaa"
→"oatGmaaaa"
- For
"Latin"
(word 4):- Check: 'L' is a consonant
- Transformation: Remove 'L' →
"atin"
, then"atin" + "L" + "ma" + "aaaa"
→"atinLmaaaaa"
- For
-
Joining the Words:
- Combine the transformed words with spaces to form the final output.
Common Mistakes and Edge Cases
-
Case Sensitivity:
Not checking for vowels in both uppercase and lowercase can lead to incorrect results. -
Incorrect Indexing:
Forgetting to start the count from 1 for appending the "a"s can result in off-by-one errors. -
Empty Input:
Although constraints specify a non-empty string, it is good practice to consider what should happen if an empty string is provided. -
Punctuation or Special Characters:
The problem assumes words contain only letters. Handling punctuation is not required unless specified by the interviewer.
Alternative Variations
-
Pig Latin Variation:
Instead of appending "ma" and extra "a"s, you might be asked to move the first consonant cluster to the end of the word and then append "ay". -
Different Suffixes:
The problem can be varied by changing the suffixes (for example, appending a different set of characters based on word position or vowel/consonant status).
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