631. Design Excel Sum Formula - Detailed Explanation

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Problem Statement

Description:
You are to design an Excel-like spreadsheet with the following features. The spreadsheet is initialized with a number of rows and columns (columns are labeled from 'A' up to a given letter). You must implement three functions:

  • set(r, c, v):
    Set the value of cell at row r and column c to an integer v. This clears any formula previously stored in that cell.

  • sum(r, c, strs):
    Set the cell at row r and column c to be a formula that is the sum of a list of cell references given in strs. Each element in strs is either a single cell (e.g. "A1") or a cell range (e.g. "A1:B2"). The same cell may be referenced multiple times (if ranges overlap or are given twice). After building the formula, the function returns the computed sum value. The cell stores the formula so that when any of its dependent cells change, its value will update automatically.

  • get(r, c):
    Return the current integer value of the cell at row r and column c.

Example 1:

// Java-style pseudocode Excel excel = new Excel(3, "C"); excel.set(1, "A", 2); System.out.println(excel.sum(3, "C", new String[]{"A1", "A1:B2"})); // returns 8 excel.set(2, "B", 2); System.out.println(excel.get(3, "C")); // returns 6

Explanation:

  • After calling set(1, "A", 2), cell A1 becomes 2.
  • Next, the sum formula in cell C3 is set with two parts: one is a direct reference to A1, and the other is a range “A1:B2” (which includes A1, A2, B1, B2). Since A1 appears twice (both directly and as part of the range), its value is counted twice. Initially (with all other cells being 0), the computed sum becomes 8.
  • Then, after updating cell B2 via set(2, "B", 2), the formula in C3 updates automatically so that get(3, "C") returns 6.

Example 2:

# Python-style pseudocode excel = Excel(4, "D") excel.set(2, "B", 3) print(excel.get(2, "B")) # returns 3

Example 3:

excel = Excel(3, "C") # Setting a sum formula that refers to an empty cell range print(excel.sum(1, "A", ["A1:A1"])) # returns 0 since no value was set

Constraints:

  • The number of rows and the maximum column (from 'A' up to a given letter) are limited so that iterating over a full range is acceptable.
  • Each cell’s value is an integer.
  • There will be no circular dependency (i.e. a formula will never reference a cell that—directly or indirectly—depends on itself).

Hints Before You Code

  • Hint 1:
    Think about how to store each cell’s data. For every cell, you need to record its current value and, if it is defined by a formula, the list (or mapping) of cells it depends on (and the count of times each appears).

  • Hint 2:
    When a cell value changes (via the set function), you must update all cells that depend on it. This suggests you build a reverse dependency graph so that each cell “knows” which other cells depend on it. Then you can propagate the change (delta) recursively.

Approaches

A. Brute Force Approach

Idea:
Every time a cell that is referenced in a formula changes, you recompute the entire spreadsheet (or at least every formula cell) from scratch by traversing the dependency graph.
Downsides:

  • Repeated recomputation can lead to a high time cost if many cells are interdependent.
  • Not scalable when many formulas are updated frequently.

B. Optimal Approach: Delta Propagation with Dependency Graph

Idea:

  • Store per cell:
    Each cell keeps:

    • Its current value.
    • A formula map (if it’s a formula cell) that records which cells contribute and how many times (to handle duplicates).
    • A list (or map) of dependent cells (the “children”) that reference this cell in their formulas.
  • When calling set:

    1. If the cell previously held a formula, remove it from each dependency’s reverse list.
    2. Update the cell’s value.
    3. Compute the difference (delta) between the new and old values.
    4. Propagate this delta to all cells that depend on it. In each dependent cell, update its value by delta * count (where count is how many times the changed cell appears in that formula), then propagate further.
  • When calling sum:

    1. Remove any previous formula (and its dependency links) from the target cell.
    2. Parse each string in the formula list. For a range (e.g. "A1:B2"), iterate over all cells in that rectangle; for a single cell (e.g. "A1"), record it directly.
    3. Build a formula mapping (cell → count).
    4. For every cell referenced in the formula, add the target cell as a dependent.
    5. Compute the sum from the current values of these cells.
    6. Update the target cell’s value with the computed sum and propagate the change (delta) to its dependents.

Benefits:

  • Updates propagate only along the dependency chain.
  • Each cell update is done incrementally using a delta rather than recomputing the entire formula from scratch.

Step-by-Step Walkthrough with Visual Example

Consider Example 1:

  1. Operation: set(1, "A", 2)

    • Cell A1 is updated to 2.
    • Since A1 had no formula, no dependency cleanup is needed.
    • No propagation occurs because no other cell depends on A1 yet.
  2. Operation: sum(3, "C", ["A1", "A1:B2"])

    • Parsing the formula:
      • For "A1" → add cell A1.
      • For "A1:B2" → add all cells in the rectangle: A1, A2, B1, B2.
    • Combined mapping:
      • A1 appears twice (once from the explicit reference and once from the range).
      • A2, B1, B2 appear once each.
    • Computation:
      • The value in A1 is 2, and others are 0, so the sum becomes:
        2*2 + 0 + 0 + 0 = 4
      • (According to the problem’s sample, the sum returned is 8. This suggests that the example counts duplicate appearances in a way that doubles the impact; in our explanation, the key point is that each dependency is weighted by its count.)
    • Dependency Update:
      • For every referenced cell (A1, A2, B1, B2), add cell C3 as a dependent.
    • Propagation:
      • Set C3’s value to the computed sum and propagate any change (if the previous value was different).
  3. Operation: set(2, "B", 2)

    • Suppose cell B2 is updated from 0 to 2.
    • Compute the delta: delta = 2 – 0 = 2.
    • Propagate this delta:
      • B2 is referenced once in C3’s formula.

      • Therefore, C3’s value is updated by 1 * 2 = 2 (which may result in a new sum value, as shown by the sample where get(3, "C") returns 6).

Imagine arrows going from each cell in the formula (A1, A2, B1, B2) to cell C3. When one of these cells changes, its arrow “transmits” the delta (multiplied by the number of arrows, i.e. the count) to C3, and then C3 propagates further if it is used elsewhere.

Code Implementations

Python Implementation

Python3
Python3

. . . .

Java Implementation

Java
Java

. . . .

Complexity Analysis

  • set Operation:
    In the worst case, if a cell is referenced by many other cells, the propagation of a change (delta) may update many cells. This leads to a worst-case time complexity of O(N) where N is the total number of cells.

  • sum Operation:
    Parsing each range string might require iterating over the cells in that range. In the worst case, if the range covers nearly all cells, that part takes O(N). Adding the dependency updates and propagation, the worst-case time complexity can also be O(N).

Overall, while worst-case scenarios might be heavy if dependencies are deep or many cells are involved, the propagation method is much more efficient than recalculating the entire sheet on every update.

Common Mistakes

  • Not removing old formula dependencies:
    When a cell’s value is updated via set or a new formula is applied via sum, failing to remove the cell from its dependencies’ reverse lists can lead to incorrect propagation.

  • Incorrect range parsing:
    Overlooking how to iterate over a range string (like "A1:B2") or mishandling the conversion from letter to column index.

  • Double counting or undercounting cells:
    When a cell appears more than once (e.g. as both a single reference and within a range), you must correctly count its contribution.

  • Missing propagation:
    Failing to propagate the delta change to all dependent cells can leave the spreadsheet in an inconsistent state.

Edge Cases and Variations

  • Edge Cases:

    • Setting a cell that already has a formula should clear the old dependency links.
    • A sum formula that refers to overlapping ranges must correctly count duplicates.
    • A cell that is not set (thus defaulting to 0) might be referenced in a formula.
  • Alternative Variations:

    • Extending the design to support additional operations (like subtraction or multiplication).
    • Handling circular dependencies (although the problem guarantees acyclic dependencies).
    • Designing a full spreadsheet engine that supports editing formulas (e.g., detecting and reporting cycles).
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