365. Water and Jug Problem - Detailed Explanation
Problem Statement
You are given two jugs with capacities x and y liters respectively, and an infinite water supply. Your task is to determine whether it is possible to measure exactly z liters using these two jugs. You can perform operations such as filling a jug completely, emptying a jug, or pouring water from one jug to the other until either the first jug is empty or the second jug is full.
Examples
Example 1
Input: x = 3, y = 5, z = 4
Output: true
Explanation:
One possible solution is:
- Fill the 5-liter jug.
- Pour water from the 5-liter jug into the 3-liter jug until it is full. Now, you have 2 liters remaining in the 5-liter jug.
- Empty the 3-liter jug.
- Pour the 2 liters from the 5-liter jug into the 3-liter jug.
- Fill the 5-liter jug again.
- Pour water from the 5-liter jug into the 3-liter jug until it is full. The 3-liter jug already has 2 liters, so it needs only 1 liter more, leaving exactly 4 liters in the 5-liter jug.
Example 2
Input: x = 2, y = 6, z = 5
Output: false
Explanation:
It is impossible to measure exactly 5 liters with jug capacities of 2 and 6 liters under the given operations.
Constraints
- The capacities x, y, and the target z are non-negative integers.
- You have an infinite supply of water.
- The operations allowed are filling a jug completely, emptying a jug, or pouring water from one jug to the other.
Hints
- Think about the problem in terms of number theory. Specifically, any amount of water that can be measured using these operations is a linear combination of x and y.
- Consider using Bézout's identity, which states that for any integers a and b, there exist integers m and n such that m * a + n * b = gcd(a, b). This means that any measurable quantity must be a multiple of the greatest common divisor (gcd) of x and y.
- The target z must be less than or equal to the sum of the two jug capacities (i.e., z ≤ x + y).
Approach
The key observation is that the water jug problem is essentially a question of whether there exists a solution to the Diophantine equation:
m * x + n * y = z
According to Bézout's identity, this equation has a solution in integers m and n if and only if z is a multiple of the gcd(x, y). However, even if z is a multiple of the gcd, you cannot measure more water than the sum of both jugs, so an additional constraint is z ≤ x + y.
Thus, the solution can be summarized in these steps:
- If z is 0, return true immediately (since you can have both jugs empty).
- If z is greater than x + y, return false because you cannot measure more water than the total capacity.
- Otherwise, calculate the gcd of x and y.
- Check if z is a multiple of the gcd. If yes, return true; otherwise, return false.
Detailed Explanation
Understanding Bézout's Identity
Bézout's identity states that for any integers x and y, there exist integers m and n such that:
m * x + n * y = gcd(x, y)
This implies that the only amounts of water that can be measured using the jugs are multiples of gcd(x, y). Therefore, if z is not a multiple of gcd(x, y), there is no way to measure z liters using the operations provided.
Considering the Capacity Constraint
Even if z is a multiple of gcd(x, y), you must be able to physically hold z liters using the two jugs. Since you can only have at most x + y liters at any time (when both jugs are full), z must be less than or equal to x + y.
Putting It All Together
The algorithm can be implemented as follows:
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Check if z is 0. If yes, return true.
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Check if z > x + y. If yes, return false.
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Compute gcd(x, y).
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Check if z is divisible by the computed gcd. If it is, return true; otherwise, return false.
Python Code
Java Code
Complexity Analysis
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Time Complexity:
- The main computation is the calculation of the gcd, which runs in O(log(min(x, y))) time using the Euclidean algorithm.
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Space Complexity:
- O(1) extra space is used.
Common Pitfalls
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Forgetting to check the case where z is 0.
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Not verifying that z is less than or equal to the total capacity (x + y).
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Not using the gcd to check the divisibility condition, which is central to determining if the water measurement is possible.
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